fastjson介绍与使用

摘要:设置返回数据的类型(json)
pom.xml文件中加入依赖依赖:
<dependency>
	<groupId>com.alibaba</groupId>
	<artifactId>fastjson</artifactId>
	<version>1.0.4</version>
</dependency>

Spring中的配置(用来支持解析@ResponseBody

 

<bean id="fastJsonHttpMessageConverter"
      class="com.alibaba.fastjson.support.spring.FastJsonHttpMessageConverter">
    <property name="supportedMediaTypes">
        <list>
            <value>application/json</value>
        </list>
    </property>
</bean>
<bean class=" org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter">
    <property name="messageConverters">
        <list>
            <ref bean="fastJsonHttpMessageConverter"/>
        </list>
    </property>
</bean>

 

对象转json

JSON.toJSONString(Bean, true);// 后面一个参数是是否保持顺序

 

json字符转对象

public static HashMap<String, Object> deserilizableForMapFromFile(String InputfilePathName) throws IOException {
    Map<String, Object> map = JSON.parseObject(InputfilePathName, new TypeReference<Map<String, Object>>() {
    });
    return (HashMap<String, Object>) map;
}

public static ApiData deserilizableForApidata(String str) {
    ApiData apiData = JSON.parseObject(str, ApiData.class);
    return apiData;
}

 

其他用法:

1.String转JSONObject

String jsonMessage = "{\"语文\":\"88\",\"数学\":\"78\",\"计算机\":\"99\"}";

JSONObject  myJson = JSONObject.fromObject(jsonMessage);

2.String转JSONArray

String jsonMessage = "[{'num':'成绩', '外语':88, '历史':65, '地理':99, 'object':{'aaa':'1111','bbb':'2222','cccc':'3333'}}," +
          "{'num':'兴趣', '外语':28, '历史':45, '地理':19, 'object':{'aaa':'11a11','bbb':'2222','cccc':'3333'}}," +
          "{'num':'爱好', '外语':48, '历史':62, '地理':39, 'object':{'aaa':'11c11','bbb':'2222','cccc':'3333'}}]";
 JSONArray myJsonArray = JSONArray.fromObject(jsonMessage);
 System.out.println(myJsonArray);

3.String转Map

(1)

 

String jsonMessage = "{\"语文\":\"88\",\"数学\":\"78\",\"计算机\":\"99\"}";

JSONObject  myJson = JSONObject.fromObject(jsonMessage);

Map m = myJson; 

(2) (需要引入jackjson的core、databind、annotations三个jar包  )

String json = "{\"PayPal key2\":\"PayPal value2\",\"PayPal key1\":\"PayPal value1\",\"PayPal key3\":\"PayPalvalue3\"}";  

ObjectMapper mapper = new ObjectMapper();    
 Map<String,Object> m = mapper.readValue(json, Map.class);  

(3)(特殊格式的String)

 

String a ="{se=2016, format=xml, at=en co=3}";

a =  a.substring(1, a.length()-1);
Map docType = new HashMap();  
Java.util.StringTokenizer items;  
for(StringTokenizer entrys = new StringTokenizer(a, ", ");entrys.hasMoreTokens();   
docType.put(items.nextToken(), items.hasMoreTokens() ? ((Object) (items.nextToken())) : null)){  
     items = new StringTokenizer(entrys.nextToken(), "=");  
   }

 

4.JSONObject、JSONArray,Map转String

JSONObject——String:

System.out.println(myJsonObject);//可直接输出JSONObject的内容

myJsonObject.toString();

JSONArray——String:

System.out.println(myJsonArray);//可直接输出myJsonArray的内容

myJsonArray.toString();

Map——String:

System.out.println(map);//可直接输出map的内容

map.toString();

 

5.JSONObject转JSONArray

 

 

6.JSONObject转Map

 

JSONObject  myJson = JSONObject.fromObject(jsonString);

Map m = myJson; 

 

7.JSONArray转JSONObject

 

 

  for(int i=0 ; i < myJsonArray.length() ;i++)
   {
    //获取每一个JsonObject对象
    JSONObject myjObject = myJsonArray.getJSONObject(i);

 

 

}

 

8.JSONArray转Map

 

 

9.Map转JSONObject

JSONObject json = JSONObject.fromObject( map );   

 

10.Map转JSONArray

   JSONArray.fromObject(map);

11.List转JSONArray
JSONArray jsonArray2 = JSONArray.fromObject( list );      

 

12.JSONArray转List

List<Map<String,Object>> mapListJson = (List)jsonArray;

发布者:songJian   点击数:564   发布时间:2018-01-09 17:34:14   更新时间:2018-07-03 14:48:57
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